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4.9x^2-14.48x+6=0
a = 4.9; b = -14.48; c = +6;
Δ = b2-4ac
Δ = -14.482-4·4.9·6
Δ = 92.0704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14.48)-\sqrt{92.0704}}{2*4.9}=\frac{14.48-\sqrt{92.0704}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14.48)+\sqrt{92.0704}}{2*4.9}=\frac{14.48+\sqrt{92.0704}}{9.8} $
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